Farragut Place
( "North Plainfield", "Somerset County", "New Jersey", United States )
residential
Wed, Nov 5 00:15
Wed, Nov 5 00:15
40.6322946466443
-74.4207187841965
Farragut Place coordinates are 40°37'56" N and 74°25'15" W in DMS (Degrees Minutes and Seconds) or 40.6322 latitude and -74.420 longitude (in decimal degrees). Farragut Place has an elevation of ~? meters. Current local time is 00:15; the sun rises at 06:33 and sun sets at 16:48 local time (America/New_York UTC/GMT-5).
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