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Farragut Place

  ( Amityville, "Suffolk County", "New York", United States )
residential  time Thu, Nov 13 02:54
40.6603947854924 -73.4121879497853

Farragut Place coordinates are 40°39'37" N and 73°24'44" W in DMS (Degrees Minutes and Seconds) or 40.6603 latitude and -73.412 longitude (in decimal degrees). Farragut Place has an elevation of ~? meters. Current local time is 02:54; the sun rises at 06:39 and sun sets at 16:36 local time (America/New_York UTC/GMT-5).
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