Stonybrook Place
( "North Plainfield", "Somerset County", "New Jersey", United States )
residential
Tue, Jun 17 12:54
Tue, Jun 17 12:54
40.6270049723308
-74.4392090507719
Stonybrook Place coordinates are 40°37'37" N and 74°26'21" W in DMS (Degrees Minutes and Seconds) or 40.6270 latitude and -74.439 longitude (in decimal degrees). Stonybrook Place has an elevation of ~? meters. Current local time is 12:54; the sun rises at 05:26 and sun sets at 20:31 local time (America/New_York UTC/GMT-4).
Time zone for Stonybrook Place is UTC/GMT-5 but since Daylight Saving Time (DST) is in effect the current time zone is UTC/GMT-4.
Time zone for Stonybrook Place is UTC/GMT-5 but since Daylight Saving Time (DST) is in effect the current time zone is UTC/GMT-4.
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